JEE Advanced Model Paper 15 with solutions for online practice

Since ∠B = ∠C = 75°
∠BAC = 30° , ∠BOC = 60°
ΔOBC is equilateral BC=OB=3
M is the midpoint of BC
OM = √9−

9

4

=

3√3

2

Equation of BC is x = -

3√3

2

Solving with x2+y2 = 9 we get the points (

−3√3

2

,±

3

2

)
∴ Product of the ordinates of B and C =

3

2

(−

3

2

) = -

9

4