Let f(x) be a differentiable non-decreasing function such that \int^{x}_{0} (f(t))^3 dt = 1/x^2(\int^{x}_{0}f(t)dt)^3 ∀ x ∊ R - {0} and f(1) . If \int^{x}_{0} f (t) dt = g (x) then \frac{xg'(x)}{g(x)} is

Correct Answer is : always equal to 1

JEE Advanced Model Paper 15 with solutions for online practice

Question : 41 of 60

Marks: +1, -0

Let f(x) be a differentiable non-decreasing function such that

∫

(f(t))3 dt =

(

∫

f(t)dt)3 ∀ x ∊ R - {0} and f(1) . If

∫

f (t) dt = g (x) then

xg′(x)

g(x)

Go to Question:

Prev Question

Next Question