The same quantity of an ideal diatomic gas is undergone for two cyclic processes(1) and (2) as shown. \eta_1 and \eta_2 are the efficiencies of (1) and (2) respectively. Then \eta_1/\eta_2 = \frac{1+7x}{15+y} . What is the value of (x + y)?

JEE Advanced Model Paper 11 with solutions for online practice

Question : 7 of 60

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The same quantity of an ideal diatomic gas is undergone for two cyclic processes(1) and (2) as shown. η1 and η2 are the efficiencies of (1) and (2) respectively. Then

η1

η2

1+7x

15+y

. What is the value of (x + y)?

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