JEE Advanced Model Paper 10 with solutions for online practice

Question : 26 of 54

Marks: +1, -0

The boiling point and freezing point of pure benzene are 80.1°C and 5.5°C. Some amount of benzoic acid is addedinto it. Now it boils at 83.1°C and freezes at 2.5°C. Select the correct options (kf= 5.12 K.kg. mol−1 , Kb = 2.57 K kg mol−1)

Benzoic acid dissociate as acid at low temperature so i > 1.
If molality of solution is 1.17 mol/kg no association or dissociation takes place at boiling point of solution.
Calculation of molar mass of benzoic acid from depression in freezing point can give information about van’tHoff factor
van’t Hoff factor is 0.5 (approx) at freezing point of solution if molality of solution is 1.17 mol/kg

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