Vector Algebra

Section: Mathematics

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Question : 15 of 38

Marks: +1, -0

Let O be the origin and let PQR be an arbitrary triangle. The point S is such that

→

OP

⋅

→

OQ

+

→

OR

⋅

→

OS

=

→

OR

⋅

→

OP

+

→

OQ

⋅

→

OS

=

→

OQ

⋅

→

OR

+

→

OP

⋅

→

OS

Then the triangle PQ has S as its:

[JEE Adv 2017 P2]

circumcentre
orthocenter
incentre
centroid

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