Limits, Continuity and Differentiability

Section: Mathematics

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Question : 40 of 51

Marks: +1, -0

For a ∈ R (the set of all real numbers), a≠ -1,

lim

n→∞

(1a+2a+....+na)

(n+1)(a−1)[(na+1)+(na+2)+....+(na+n)]

=

1

60

. Then a =

[JEE Adv 2013 P2]

5
7
−
15
2
−
17
2

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