Limits, Continuity and Differentiability

Section: Mathematics

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Question : 28 of 51

Marks: +1, -0

Let f(x)=

1−x(1+|1−x|)

|1−x|

cos(

1

1−x

) for x≠1Then :

[JEE Adv 2017 P2]

lim
x→1−
f(x) does not exist
lim
x→1+
f(x) does not exist
lim
x→1−
f(x)=0
lim
x→1+
f(x)=0

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