Let f : (0,1)→R be defined by f (x) = \frac{b-x}{1-bx}, where b is a constant such that 0 < b < 1. Then [JEE Adv 2011 P2]

Correct Answer is : f is not invertible on (0, 1).

f ≠ f^{ −1} on (0, 1) and f' (b) = 1/{f'(0)}.

f = f^{ −1} on (0, 1) and f' (b) = 1/{f'(0)}.

f^{-1} is differentiable on (0, 1).

Functions

Section: Mathematics

Question : 23 of 30

Marks: +1, -0

Let f : (0,1)→R be defined by f (x) =

b−x

1−bx

, where b is a constant such that 0 < b < 1. Then

[JEE Adv 2011 P2]

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