Differential Equations
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Question : 23 of 23
Marks:
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Let a solution y = y(x) of the differential equation
x √ x 2 − 1 d y - y √ y 2 − 1 dx = 0 satisfy y (2) =
STATEMENT 1: y (x) =s e c ( s e c − 1 x −
) .
STATEMENT 2: y(x) is given by
=
− √ 1 −
STATEMENT 1: y (x) =
STATEMENT 2: y(x) is given by
[JEE Adv 2008 P2]
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