Definite Integration
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Question : 46 of 46
Marks:
+1,
-0
Consider the functions defined implicitly by the equation y3 − 3y + x = 0 on various intervals in the real line. If x ∈ (-∞, -2) ∪ (2, ∞), the equation implicitly defines a unique real valued differentiable function y = f(x).
If x ∈(-2, 2), the equation implicitly defines a unique real valued differentiable function y = g(x) satisfying g(0) = 0.
g ′ ( x ) d x = ?
If x ∈(-2, 2), the equation implicitly defines a unique real valued differentiable function y = g(x) satisfying g(0) = 0.
[JEE Adv 2008 P1]
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