The following integral \int^{\pi/2}_{\pi/4}(2\text{cosec} x)^17dx is equal to [JEE Adv 2014 P2]

Correct Answer is : log(1+√2)∫02(eu+e−u)16 du

\int^{\log(1+\sqrt2)}_{0} 2(e^u + e^{-u})^16 du

\int^{\log(1+\sqrt2)}_{0} (e^u + e^{-u})^17 du

\int^{\log(1+\sqrt2)}_{0} (e^u - e^{-u})^17 du

\int^{\log(1+\sqrt2)}_{0} 2(e^u - e^{-u})^16 du

Definite Integration

Section: Mathematics

Question : 31 of 46

Marks: +1, -0

The following integral

∫

(2cosec‌x)17dx is equal to

[JEE Adv 2014 P2]

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