Let f:\mathbb{R}\to\mathbb{R} be a function defined by f(x)=\{\table\[x],x\leq2 ; 0,x\leq2,where [x] is the greater integer less than or equal to x.If I=\int^{2}_{-1}\frac{xf(x^2)}{2+f(x+1)}dx then the value of (4l-1)is [JEE Adv 2015 P1]

Definite Integration

Section: Mathematics

Question : 28 of 46

Marks: +1, -0

Let f:ℝ→ℝ be a function defined by f(x)={

[x]	x≤2
0	x≤2

,where [x] is the greater integer less than or equal to x.If I=

∫

−1

xf(x2)

2+f(x+1)

dx then the value of (4l−1)is

[JEE Adv 2015 P1]

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