Let S= \{(x, y) \in \times : x \geq 0, y \geq 0, y^2 \leq 4 x, y^2 \leq 12-2 x. and 3 y+\sqrt{8} x \leq 5 \sqrt{8}\}. If the area of the region S is \alpha \sqrt{2}, then \alpha is equal to [JEE Adv 2024 P2]

Application of Integration

Section: Mathematics

Question : 2 of 28

Marks: +1, -0

Let S={(x,y)∈ × :x≥0,y≥0,y2≤4x,y2≤12−2x. and 3y+√8x≤5√8}. If the area of the region S is α√2, then α is equal to

[JEE Adv 2024 P2]

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