Application of Integration

Section: Mathematics

© examsiri.com

Question : 16 of 28

Marks: +1, -0

Let f:ℝ→ℝ be a continuous odd function,which vanishes exactly at one point and f(1)=

1

2

.Suppose that F(x)=

x

∫

−1

f(t)dt for all x∊[−1,2] and G(x)=

x

∫

−1

t|f(f(t))|dt for all x∊[−1,2].If

lim

x→1

F(x)

G(x)

=

1

14

then the value of f(

1

2

) is

[JEE Adv 2015 P2]

Your Answer:

Go to Question:

Prev Question

Next Question