Consider the following lists: List-I List-II (I) \{x \in[-\frac{2 \pi}{3}, \frac{2 \pi}{3}]: \cos x+\sin x=1\} (P) has two elements (II) \{x \in[-\frac{5 \pi}{18}, \frac{5 \pi}{18}]: \sqrt{3} \tan 3 {\x}=1\} (Q) has three elements (III) \{x \in[-\frac{6 \pi}{5}, \frac{6 \pi}{5}]: 2 \cos (2 x)=\sqrt{3}\} (R) has four elements (IV) \{x \in[-\frac{7 \pi}{4}, \frac{7 \pi}{4}]: \sin x-\cos x=1\} (S) has five elements (T) has six elements The correct option is: [JEE Adv 2022 P1]

Correct Answer is : (I)⟶(P);(II)⟶(P);(III)⟶(T);(IV)⟶(R)

( {\I}) \to( {\P}) ;( {\II}) \to( {\S}) ;( {\III}) \to( {\P}) ;( {\IV}) \to( {\S})

( {\I}) \rightarrow( {\P}) ;( {\II}) \rightarrow( {\P}) ;( {\III}) \rightarrow( {\T}) ;( {\IV}) \rightarrow( {\R})

( {\I}) \rightarrow( {\Q}) ;( {\II}) \to( {\P}) ;( {\III}) \to( {\T}) ;( {\IV}) \to( {\S})

( {\I}) \to( {\Q}) ;( {\II}) \rightarrow( {\S}) ;( {\III}) \to( {\P}) ;( {\IV}) \to( {\R})

Trigonometric Functions & Equations

Section: Mathematics

Question : 6 of 30

Marks: +1, -0

Consider the following lists:

List-I

List-II

(I)

{x∈[−‌

2π

,‌

2π

]:cos‌x+sin‌x=1}

(P)

has two elements

(II)

{x∈[−‌

5π

,‌

5π

]:√3‌tan‌3‌x=1}

(Q)

has three elements

(III)

{x∈[−‌

6π

,‌

6π

]:2‌cos(2x)=√3}

(R)

has four elements

(IV)

{x∈[−‌

7π

,‌

7π

]:sin‌x−cos‌x=1}

(S)

has five elements

(T)

has six elements

The correct option is:

[JEE Adv 2022 P1]

(I)→(P);(II)→(S);(III)→(P);(IV)→(S)
(I)⟶(P);(II)⟶(P);(III)⟶(T);(IV)⟶(R)
(I)⟶(Q);(II)→(P);(III)→(T);(IV)→(S)
(I)→(Q);(II)⟶(S);(III)→(P);(IV)→(R)

Validate

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