Sequences and Series

Section: Mathematics
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Question : 18 of 22
 
Marks: +1, -0
Let a1,a2,a3, …, a11 be real numbers satisfying a1 = 15, 272a2 > 0 and ak = 2ak1ak2 for k = 3 , 4 , ... , 11. If
a12+a22+...+a112
11
= 90, then the value of
a1+a2+...+a11
11
is equal to _____.
[JEE Adv 2010 P2]
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