Probability
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A computer producing factory has only two plants T 1 and T 2 Plant T 1 produces 20% and plant T 2 produces 80% of the total computers produced. 7% of computers produced in the factory turn outto be defective. It is known that
P(computer turns out to be defective given that is produced in plantT 1
= 10P(computer turns out to be defective given that it is produced in plantT 2
where P(E) denotes the probability of an event E. A computer produces in the factory is randomlyselected and it does not turn out to be defective. Then the probabality that it is produced in plantT 2 is
P(computer turns out to be defective given that is produced in plant
= 10P(computer turns out to be defective given that it is produced in plant
where P(E) denotes the probability of an event E. A computer produces in the factory is randomlyselected and it does not turn out to be defective. Then the probabality that it is produced in plant
[JEE Adv 2016 P1]
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