Complex Numbers

Section: Mathematics

© examsiri.com

Question : 21 of 36

Marks: +1, -0

Let zk=cos(

2kπ

10

)+isin(

2kπ

10

); k=1,2,...,9.

List-I

List-II

(P)

For eachzk there exists a zk.zj=1

(1)

True

(Q)

There exists a k∊{1,2,...9}

(2)

False

(R)

|1−z1||1−z2|....|1−z9|

10

equals

(3)

1

(S)

1−∑k=19cos(

2kπ

10

) equals

(4)

2

[JEE Adv 2014 P2]

P
1
‌‌
Q
2
‌‌
R
4
‌‌
S
3
P
2
‌‌
Q
1
‌‌
R
3
‌‌
S
4
P
1
‌‌
Q
2
‌‌
R
3
‌‌
S
4
P
2
‌‌
Q
1
‌‌
R
4
‌‌
S
3

Go to Question:

Prev Question

Next Question