Solutions

According to Henry’s law, we have
pN2 = KHxN2
0.8 × 5 = 1 × 105×xN2
xN2 = 4 × 10−5
Thus one mole of solution contains 4 × 10−5 moles of N2 and 1-4 × 10−5 ≈ 1 mole of water. Therefore, N2 from air dissolved in 10 moles of water is 10 × 4 × 10−5 moles = 4 × 10−4.