Thermodynamics

Section: Chemistry

Question : 18 of 40

Marks: +1, -0

The surface of copper gets tarnished by the formation of copper oxide. N2 gas was passed to prevent the oxide formation during heating of copper at 1250 K. However, the N2 gas contains 1 mole % of water vapour as impurity. The water vapour oxidizes copper as per the reaction given below:

2Cu(s)+H2O(g)→Cu2O(s)+H2(g)pH2

is the minimum partial pressure of H2 (in bar) needed to prevent the oxidation at 1250K. The value of In(PH2) is______.
(Given: total pressure=1 bar, R(universal gas constant)

=8JK−1mol−1,In(10)=2.3.Cu(s)

and Cu2O(s) are mutually immiscible. At 1250K:

2Cu(s)+

O2(g)→Cu2O(s);ΔG0=−78,000Jmol−1
H2(g)+

O2(g)→H2O(g);ΔG0=−1,78,000Jmol−1;G is the Gibbs energy)

[JEE Adv 2018 P2]

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