JEE Advanced 2024 Paper 1

Section: Mathematics

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Question : 3 of 51

Marks: +1, -0

Let ‌

π

2

<x<π be such that cot‌x=‌

−5

√11

. Then (sin‌‌

11x

2

)(sin‌6x−cos‌6‌x) +(cos‌

11x

2

)(sin‌6x+cos‌6‌x) is equal to

[JEE Adv 2024 P1]

‌
√11−1
2√3
‌
√11+1
2√3
‌
√11+1
3√2
‌
√11−1
3√2

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