JEE Advanced 2023 Paper 2 Solutions

A thin circular coin of mass 5‌gm and radius 4∕3‌cm is initially in a horizontal xy-plane. The coin is tossed vertically up ( +z direction) by applying an impulse of √‌

π

2

×10−2N− s at a distance 2∕3‌cm from its center. The coin spins about its diameter and moves along the +z direction. By the time the coin reaches back to its initial position, it completes n rotations. The value of n is
[Given: The acceleration due to gravity g=10ms−2 ]