JEE Advanced 2023 Paper 2 Solutions

Section: Mathematics

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Question : 37 of 51

Marks: +1, -0

For any y∈ℝ, let cot−1(y)∈(0,π) and tan−1(y)∈(−‌

π

2

,‌

π

2

). Then the sum of all the solutions of the equation

tan−1(‌

6y

9−y2

)+cot−1(‌

9−y2

6y

)=‌

2π

3

for 0<|y|<3, is equal to

[JEE Adv 2023 P2]

2√3−3
3−2√3
4√3−6
6−4√3

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