JEE Advanced 2023 Paper 2 Solutions

Section: Mathematics

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Question : 35 of 51

Marks: +1, -0

Let f:[1.∞)→ℝ be a differentiable function such that f(1)=‌

1

3

and 3‌

x

∫

1

f(t)‌dt=xf(x)−‌

x3

3

,x∈[1,∞). Let e denote the base of the natural logarithm. Then the value of f(e) is

[JEE Adv 2023 P2]

‌
e2+4
3
‌
loge4+e
3
‌
4e2
3
‌
e2−4
3

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