JEE Advanced 2022 Paper 1

Section: Chemistry

Question : 51 of 54

Marks: +1, -0

Match the rate expressions in LIST-I for the decomposition of X with the corresponding profiles
provided in LIST-II. Xs and k constants having appropriate units.

List - I

List - II

(I)
‌ rate ‌=‌

k[X]

Xs+[X]

under all possible initial concentration of X

(P)

(II)
rate =‌

k[X]

Xs+[X]

where initial concentration of X are much less than Xs

(Q)

(III)
‌ rate ‌=‌

k[X]

Xs+[X]

where initial concentration of X are much higher than Xs

(R)

(IV)
rate =‌

k[X]2

Xs+[X]

where initial concentration of X is
much higher than Xs

(S)

(T)

[JEE Adv 2022 P1]

I→P;II→Q;III→S;IV→T
I→R;II→S;III→S;IV→T
I→P;II→Q;III→Q;IV→R
I→R;II→S;III→Q;IV→R

Validate

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