JEE Advanced 2021 Paper 1

When switch is connected to position PFrom KVL,
VA−1⋅i1−1+2−2i1=VA⇒3i1=1
∴‌‌i1=‌

1

3

A
Again VA−1⋅i1−1=VB
or, VA−VB=1+i1=‌

4

3

V
Potential drop across capacitor ∆V=‌

4

3

V
∴‌‌ Charge on capacitor, q1=C∆V=1×‌

4

3

µC
q1=1.33µC
When switch is connected to position QFrom KVL,
VA−1⋅i2+2−2i2=VA⇒3i2=2
∴‌‌i2=‌

2

3

A
Again, VA−i2×1=VB
VA−VB=i1×1=‌

2

3

V
Potential difference across capacitor ∆V=‌

2

3

V
∴‌‌ Charge on capacitor, q2=C∆V=1×‌

2

3

=0.67µC