JEE Advanced 2021 Full Test 5 Paper 2

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SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded‐off to the second decimal place; e.g. XXXXX.XX).

Question : 35 of 54

Marks: +1, -0

Mg can reduce NO3− to NH3 in basic medium.
NO3−+Mg(s)+H2O→Mg(OH)2(s) +OH−(aq.)+NH3(g)
A 25.0mL sample of NO3− solution was treated with Mg. The NH3(g) was passed into 100mL of 0.15NHCl. The excess of HCl required 32.10mL of 0.10N NaOH for neutralisation. What was the molarity of NO3− ions in the original sample? Give your answer after rounding off to two decimal places.

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