A neutral particle of mass 28 {g} is at rest in a uniform magnetic field {B}=\frac{200}{3} {T}. At {t}=0, particle decays into two particle of equal mass and one of them having charge 3 \\mu{C}. Both of them move in separate paths lying in the plane perpendicular to magnetic field {B}. At later time {t}, the partide collides. (neglecting the interaction force). Calculate {{t}}/{100}.

JEE Advanced 2021 Full Test 5 Paper 2

SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded‐off to the second decimal place; e.g. XXXXX.XX).

Question : 15 of 54

Marks: +1, -0

A neutral particle of mass 28g is at rest in a uniform magnetic field B=

200

T. At t=0, particle decays into two particle of equal mass and one of them having charge 3µC. Both of them move in separate paths lying in the plane perpendicular to magnetic field B. At later time t, the partide collides. (neglecting the interaction force). Calculate

100

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