Calculate \\Delta{G}^\circ for the following cell reaction {Zn}({s})+{Ag}_{2} {O}({s})+{H}_{2} {O}(I) \\to{Zn}^{2+}(a q) +2 {Ag}({s})+2 {OH}^{-}(a q) E^\circ_{A g^{+} \/ A g} =+0.80 V and E^\circ_{Z n^{+2} \/ Z n} =-0.76 V, F=96500 (Given: {K}_{{P}} of {AgOH}=2 \\times10^{-8} )

Correct Answer is : 212 / kJ mol

JEE Advanced 2021 Full Test 5 Paper 1

PART – II

Chemistry

SECTION – A (One Options Correct Type)
This section contains 06 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct.

Question : 21 of 54

Marks: +1, -0

Calculate ΔG° for the following cell reaction Zn(s)+Ag2O(s)+H2O(I)→Zn2+(aq) +2Ag(s)+2OH−(aq)
E°Ag+∕Ag=+0.80V and E°Zn+2∕Zn=−0.76V,F=96500
(Given: KP of AgOH=2×10−8 )

-305 / kJ mol
212 / kJ mol
305 / kJ mol
301 / kJ mol

Validate

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