Calculate the maximum number of moles of gas produced in below three reactions. (i) {N}_{2(g)}+{H}_{2({g})} \stackrel{\\Delta}{────▸}{NH}_{3({g})} 310.8 {Kg} 22.2 {Kg} (ii) {CaCO}_{3({s})}\stackrel{\\Delta}{────▸}{CO}_{2({g})}+{CaO}_{({s})} 100 {Kg} (iii) {NH}_{4} {NO}_{3({s})}\stackrel{\\Delta}{────▸}{H}_{2} {O}_{(l)}+{N}_{2} {O}_{({g})} 80 {Kg}

JEE Advanced 2021 Full Test 3 Paper 2

SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded-off to the SECOND DECIMAL PLACE; e.g. XXXXX. XX).

Question : 36 of 54

Marks: +1, -0

Calculate the maximum number of moles of gas produced in below three reactions.
(i) N2(g)+H2(g)

────▸

NH3(g)
310.8Kg22.2Kg
(ii) CaCO3(s)

────▸

CO2(g)+CaO(s)
100Kg
(iii) NH4NO3(s)

────▸

H2O(l)+N2O(g)
80Kg

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