The length of focal chord {AB} of ellipse {{x}^{2}}/{4}+{{y}^{2}}/{3}=1 is: ( Given {A}=(\frac{8}{5}, {3 \\sqrt{3}/{5}))

JEE Advanced 2021 Full Test 3 Paper 1

PART – III

Mathematics

SECTION – A (One Options Correct Type)
This section contains 06 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct.

Question : 37 of 54

Marks: +1, -0

The length of focal chord AB of ellipse

=1 is: ( Given A=(

3√3

))

4
5
16
5
32
5
64
5

Validate

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