If the EMF of the following cell is {x} \\times10^{-1}. at 25^\circ{C}, then find the value of {x}. {Ag}|{AgBr}({s}) {KBr} \||{AgCl}, {KCl}| {Ag} 5 \\times10^{-3} {M} 1 \\times10^{-1} {M} Given {K}_{\text{spAgCl }}=6 \\times10^{-10} {K}_{\text{spAgBr }}=3 \\times10^{-13} \frac{2.303 \\timesR \\timesT}{F}=0.0591

JEE Advanced 2021 Full Test 3 Paper 1

SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded‐off to the second decimal place; e.g. XXXXX.XX).

Question : 31 of 54

Marks: +1, -0

If the EMF of the following cell is x×10−1. at 25°C, then find the value of x.
Ag|AgBr(s)KBr||AgCl,KCl|Ag
5×10−3M1×10−1M
Given KspAgCl =6×10−10
KspAgBr =3×10−13

2.303×R×T

=0.0591

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