Shortest distance between lines \frac{x-6}{1}=\frac{y-2}{-2}=\frac{z-2}{2} and \frac{x+4}{3}=\frac{y}{-2}=\frac{z+1}{-2} is d then 100 {d}+\frac{1}{2}=

JEE Advanced 2021 Full Test 2 Paper 1

SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded‐off to the second decimal place; e.g. XXXXX.XX).

Question : 50 of 54

Marks: +1, -0

Shortest distance between lines

x−6

y−2

−2

z−2

and

x+4

−2

z+1

−2

is d then 100d+

Your Answer:

Validate

Go to Question:

Prev Question

Next Question