JEE Advanced 2021 Full Test 2 Paper 1
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SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded‐off to the second decimal place; e.g. XXXXX.XX).
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded‐off to the second decimal place; e.g. XXXXX.XX).
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Question : 13 of 54
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A free neutron at rest, decays into three particles: a proton, an electron and an anti-neutrino.
0 1 n → 1 1 p + − 1 0 e + v
The rest masses are:m n = 939.5656 M e V ∕ c 2
m p = 938.2723 M e V ∕ c 2 , m e = 0.5109 M e V ∕ c 2
In a particular decay, the antineutrino was found to have a total energy (including rest mass energy) of0.0004 M e V
The rest masses are:
In a particular decay, the antineutrino was found to have a total energy (including rest mass energy) of
- Your Answer:
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