If the equation on reflection of {(x-4)^{2}}/{16}+{(y-3)^{2}}/{9}=1 about the line x-y-2=0 is 16 x^{2}+9 y^{2}+k_{1} x-36 y+k_{2}=0 then {k_{1}+k_{2}}/{22} is

JEE Advanced 2021 Full Test 1 Paper 2

SECTION – B (Single Digit Integer Type)
This section contains 06 questions. The answer to each question is a Single Digit integer ranging from 0 to 9, both inclusive.

Question : 47 of 54

Marks: +1, -0

If the equation on reflection of

(x−4)2

(y−3)2

=1 about the line x−y−2=0 is 16x2+9y2+k1x−36y+k2=0 then

k1+k2

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