Calculate \\Delta_{f} H^\circ (magnitude only) for chloride ion (aq.) from the following data: (in {kJ} ) \frac{1}{2} H_{2}(g)+\frac{1}{2} C l_{2}(g) \\toH C l(g) ; \\Delta_{f} H^\circ=-92.4 k J {HCl}({g})+{H}_{2} {O}(l) \\to{H}_{3} {O}^{+}(a q)+{Cl}^{-}(a q) ; \\DeltaH^\circ=-74.8 {kJ} \\Delta_{f} H^\circ of H^{+}(a q)=0.0 k J

JEE Advanced 2021 Full Test 1 Paper 1

SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded-off to the second decimal place; e.g. XXXXX.XX).

Question : 32 of 54

Marks: +1, -0

Calculate ΔfH° (magnitude only) for chloride ion (aq.) from the following data: (in kJ )

H2(g)+

Cl2(g)→HCl(g); ΔfH°=−92.4kJ
HCl(g)+H2O(l)→H3O+(aq)+Cl−(aq); ΔH°=−74.8kJ
ΔfH° of H+(aq)=0.0kJ

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