JEE Advanced 2020 Paper 2

In weak basic solution, permanganate ion converts into MnO2 (reduction of potassium permanganate) and iodine ion converts into iodide ( oxidation of KI)
i.e., chemical reaction is written as ..
MnO4−+I−⇔MnO2+I2
so equivalents of potassium permanganate = equivalents of I2
given no of moles of potassium permanganate =4
let n moles of I2 released for 4 moles of potassium permanganate consumed.
we know, equivalents = no of moles ×n-factor
so no of moles of KMnO4×n-factor of it= no of moles of I2×n-factor of it
⇒4×3=n×2
⇒n=6
Therefore 6 moles of I2 released for 4 moles of KMnO4 consumed.