JEE Advanced 2020 Paper 1

Section: Physics
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Question : 18 of 54
 
Marks: +1, -0
A circular disc of radius R carries surface charge density σ(r)=σ0(1−
r
R
)
,
where σ0 is a constantand r is the distance from the center of the disc. Electric flux through a large spherical surface thatencloses the charged disc completely is ϕ0. Electric flux through another spherical surface of radius
R
4
and concentric with the disc is Ï•. Then the ratio
ϕ0
Ï•
is _______
[JEE Adv 2020 P1]
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