An infinite non conducting sheet having charge density \sigma and there is a small hole as shown in figure and there is rod of length \lambda having linear charge density \lambda and hinged in the hole as shown. If the mass of rod is {m} then time period of oscillation for small angular displacement

Correct Answer is : 2π√2m∈03σλ

\pi \sqrt{ { {m} E_{0}}/{3 \sigma \lambda}}

2 \pi \sqrt{ {2 {m} \in_{0}}/{3 \sigma \lambda}}

\frac{\pi}{2} \sqrt{ { {m} E_{0}}/{3 \sigma \lambda}}

JEE Advanced 2020 Full Test 7 Paper 2

Question : 4 of 54

Marks: +1, -0

An infinite non conducting sheet having charge density σ and there is a small hole as shown in figure and there is rod of length λ having linear charge density λ and hinged in the hole as shown. If the mass of rod is m then time period of oscillation for small angular displacement

π√‌
mE0
3σλ
2π√‌
2m∈0
3σλ
‌
π
2
√‌
mE0
3σλ
None of these

Validate

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