If p(x)=x^{4}+a x^{3}+b x^{2}+c x+d (where a, b, c, d \in R) and p(1)=10, p(2)=20, p(3)=30 then the value of (\frac{p(12)+p(-8)-10}{10000}) equals to

JEE Advanced 2020 Full Test 7 Paper 1

Question : 51 of 54

Marks: +1, -0

If p(x)=x4+ax3+bx2+cx+d (where a,b,c,d∈R) and p(1)=10,p(2)=20,p(3)=30 then the value of (‌

p(12)+p(−8)−10

10000

) equals to

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