For the given transition: {C} (graphite) \rightarrow {C} (diamond), correct options is/are

C (diamond) is more thermodynamically stable then C (graphite) at 25^{\circ} {C}

C (graphite) is more thermodynamically stable than C (diamond) at 25^{\circ} {C}

diamond will provide more heat on complete combustion at 25^{\circ} {C}

∆ {G}_{\text{transition }} of {C} (diamond) \rightarrow {C} (graphite) is -ve

JEE Advanced 2020 Full Test 7 Paper 1

Question : 30 of 54

Marks: +1, -0

For the given transition: C (graphite) ⟶C (diamond), correct options is/are

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