A circular loop of radius r, having N turns of a wire, in placed in a uniform and constant magnetic field B. The normal of the loop makes an angle \theta with the magnetic field. Its normal rotates with angular velocity \omega in such a way that it maintains the same angle \theta with the field, the emf appearing in the loop is

\frac{\pi N B \omega r^{2}}{2} \cos \theta

JEE Advanced 2020 Full Test 6 Paper 2

Question : 3 of 54

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A circular loop of radius r, having N turns of a wire, in placed in a uniform and constant magnetic field B. The normal of the loop makes an angle θ with the magnetic field. Its normal rotates with angular velocity ω in such a way that it maintains the same angle θ with the field, the emf appearing in the loop is

‌
πNBωr2
2
‌
πNBωr2
2
‌cos‌θ
πNBωr2
Zero

Validate

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