At t=0, switch is closed to position 1 . Capacitor is initially uncharged. At t=\frac{\pi}{2 \omega}, switch is shifted to position 2 . Then current as a function of time t is (\omega is the angular frequency =\frac{1}\sqrt{L C})

Correct Answer is : CV0ωcosωt

{CV}_{0} \omega \cos \omega {t}

{CV}_{0} \omega(1-\cos \omega {t})

{CV}_{0} \omega(1-\sin \omega {t})

{CV}_{0} \omega \sin \omega {t}

JEE Advanced 2020 Full Test 5 Paper 2

Question : 7 of 54

Marks: +1, -0

At t=0, switch is closed to position 1 . Capacitor is initially uncharged.
At t=‌

2ω

, switch is shifted to position 2. Then current as a function of time t is (ω is the angular frequency =‌

√LC

)

Go to Question:

Prev Question

Next Question