The position vector of a particle moving in space is given by \overrightarrow{ {r}}=(1+2 \cos 2 \omega {t}) \stackrel{⋀}{ {i}}+(3 \sin ^{2} \omega {t})\stackrel{⋀}{ {j}+(3 {t})\stackrel{⋀}{ {k}} in the ground frame. All the units are in {Sl}. Choose the correct statement (s):

Correct Answer is : The particle executes SHM in a frame S moving along the positive z-axis with a velocity of 3m∕s

The particle executes SHM in the ground frame about the mean position (1, \frac{3}{2}, 3 t)

The particle executes SHM in a frame S moving along the positive z-axis with a velocity of 3 {m} \/ {s}

The amplitude of the SHM of the particle in frame S is \frac{5}{2} m.

The line of the SHM of the particle is parallel to the vector (\frac{4}{5} \hat{i}-\frac{3}{5} \hat{j}).

JEE Advanced 2020 Full Test 5 Paper 1

Question : 1 of 54

Marks: +1, -0

The position vector of a particle moving in space is given by

→

=(1+2‌cos‌2‌ω‌t)

⋀

+(3sin2ωt)

⋀

+(3t)

⋀

in the ground frame. All the units are in Sl. Choose the correct statement (s):

The particle executes SHM in the ground frame about the mean position (1,‌
3
2
,3t)
The particle executes SHM in a frame S moving along the positive z-axis with a velocity of 3m∕s
The amplitude of the SHM of the particle in frame S is ‌
5
2
m.
The line of the SHM of the particle is parallel to the vector (‌
4
5
∧
i
−‌
3
5
∧
j
).

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