If y=f(x) and y=g(x) are symmetrical about the line x=\frac{\alpha+\beta}{2}, then \int_{\alpha}^{\beta} f(x) g^{'}(x) d x is equal to

\int_{\alpha}^{\beta} f^{'}(x) g(x) d x

-\int_{\alpha}^{\beta} f^{'}(x) g(x) d x

\frac{1}{2} \int_{\alpha}^{\beta}(f(x) g^{'}(x)-f^{'}(x) g(x)) d x

\frac{1}{2} \int_{\alpha}^{\beta}(f(x) g^{'}(x)+f^{'}(x) g(x)) d x

JEE Advanced 2020 Full Test 4 Paper 2

Question : 40 of 54

Marks: +1, -0

If y=f(x) and y=g(x) are symmetrical about the line x=‌

α+β

, then

∫

f(x)g′(x)dx is equal to

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