JEE Advanced 2020 Full Test 3 Paper 2

© examsiri.com

Question : 41 of 54

Marks: +1, -0

lim

x→1

‌

nxn+1−(n+1)xn+1

(ex−e)‌sin‌π‌x

where n=100 is equal to:

‌
5050
πe
‌
100
πe
−‌
5050
πe
−‌
4950
πe

Go to Question:

Prev Question

Next Question