JEE Advanced 2020 Full Test 3 Paper 2

Question : 31 of 54

Marks: +1, -0

A dilute solution contains 't' moles of solute X in 1 kg of solvent with molal elevation constant Kb. The solute dimerises in the solution according to the following equation. The degree of association is α.
2X⇌X2

The degree of association α=‌
2(Kbt−∆Tb)
KbT
The molecular mass observed will be lesser than actual molecular mass
The colligative properties observed will be ∆Tb‌ obs ‌<∆Tb‌ theoretical ‌;∆Tf‌ obs ‌<∆Tf‌ theoretical ‌ ∆P‌obs ‌<∆P‌theoretical ‌
The equilibrium constant for the process can be expressed as: K=‌
Kb(Kbt−∆Tb)
[2∆Tb−Kbt]2

Validate

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