Consider the decay { }^{238} {\Pu} \to{ }^{234} {\U}+{ }^{4} {\He} The atomic masses are given as { }^{238}_{238.04955u}{\Pu} { }^{234}_{234.04095u}{\U} { }^{4}_{4.002633u}{\He} Neglecting the recoil of the residual nucleus

the kinetic energy of the \alpha particle emitted is 5.58 {MeV}

the kinetic energy of the \alpha particle emitted is 5.58 {eV}

conservation of electric charge is valid for the given reaction

conservation of electric charge is not valid for the given reaction

JEE Advanced 2020 Full Test 3 Paper 2

Question : 10 of 54

Marks: +1, -0

Consider the decay ‌238‌Pu→‌234U+‌4‌He The atomic masses are given as
‌238.04955u238‌Pu ‌234.04095u234U ‌4.002633u4‌He
Neglecting the recoil of the residual nucleus

the kinetic energy of the α particle emitted is 5.58MeV
the kinetic energy of the α particle emitted is 5.58eV
conservation of electric charge is valid for the given reaction
conservation of electric charge is not valid for the given reaction

Validate

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