Calculate ∆_{f} H^{\circ} (magnitude only) for chloride ion (aq.) from the following data: \frac{1}{2} H_{2}(g)+\frac{1}{2} C l_{2}(g) \to H C l(g) ; ∆_{f} H^{\circ}=-92.4 k J H C l(g)+H_{2} O(ℓ) \to H_{3} O^{+}(a q)+C l^{-}(a q) ; ∆ H^{\circ}=-74.8 k J ∆_{f} H^{\circ} of H^{+}(a q)=0.0 {kJ}

JEE Advanced 2020 Full Test 2 Paper 2

Question : 32 of 54

Marks: +1, -0

Calculate ∆fH∘ (magnitude only) for chloride ion (aq.) from the following data:
‌

H2(g)+‌

Cl2(g)→HCl(g);‌‌∆fH∘=−92.4kJ HCl(g)+H2O(ℓ)→H3O+(aq)+Cl−(aq);‌‌∆H∘=−74.8kJ ∆fH∘ of H+(aq)=0.0kJ

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