JEE Advanced 2020 Full Test 2 Paper 2

A positively charged particle starts at rest 25cm from a second positively charged particle which is held stationary throughout the experiment. The first particle is released and accelerates directly always from the second particle. When the first particle has moved 25cm, it has reached a velocity of 10√2m∕s. The maximum velocity (in m∕s ) that the first particle will reach is 10×x, find x?